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36y^2-3=26
We move all terms to the left:
36y^2-3-(26)=0
We add all the numbers together, and all the variables
36y^2-29=0
a = 36; b = 0; c = -29;
Δ = b2-4ac
Δ = 02-4·36·(-29)
Δ = 4176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4176}=\sqrt{144*29}=\sqrt{144}*\sqrt{29}=12\sqrt{29}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{29}}{2*36}=\frac{0-12\sqrt{29}}{72} =-\frac{12\sqrt{29}}{72} =-\frac{\sqrt{29}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{29}}{2*36}=\frac{0+12\sqrt{29}}{72} =\frac{12\sqrt{29}}{72} =\frac{\sqrt{29}}{6} $
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